20 points!! I need helpA rectangular pool is surrounded by a walk 3 meters wide. The pool is 5 meters longer than its width. If the total area of the pool and walk is 387 square meters more than the area of the pool, find the dimensions of the pool.
Accepted Solution
A:
Answer:11.33 * 16.33 meters to the nearest hundredth.Step-by-step explanation:Let the width of the pool be x meters, then the length is x+5 meters.The length of whole area = x + 5 + 2(3) = x + 11 meters and the width is x + 2(3) = x + 6 meters.So we have the equation (x + 6)(x + 11) = 387. x^2 + 17x + 66 = 387x^2 + 17x - 321 = 0x = [-17 +/- sqrt (17^2 - 4*1*-321)] / 2x = 11.33 metersSo the width is 11.3 m and the length is 16.33 meters.